'vb.net2008
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Public Class Form1
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
Dim min, max As Integer
Dim a() As Integer = {3, 2, 4, 1}
min = Proc(a)(0)
max = Proc(a)(1)
End Sub
Private Function Proc(ByVal a() As Integer)
Dim a_out(a.GetUpperBound(0)), a_m(1) As Integer
System.Array.Copy(a, a_out, a.GetUpperBound(0) + 1)
System.Array.Sort(a_out)
a_m(0) = a_out(0)
a_m(1) = a_out(a_out.GetUpperBound(0))
Return a_m
End Function
End Class
-1.52341E-13
科学计数法,10的-13次方表示此数已经接近于0了,应该是single类型的精度导致的,你把精度设置适当应该就可以了。
1、我有一个function,如下:
function b()
'...
return "abc"
end function
2、调用时,这样子用:
Response.write(b());
3、运行结果:
abc
注意:参数为动态数组;
Private Function MyF(ByRef d() As Integer)
ReDim d(4, 13) As Integer
Dim i As Integer
Dim j As Integer
Dim n As Integer
Dim MyNum(4) As Integer
For i = 1 To 4
MyNum(i) = 0
Next i
Randomize
For i = 1 To 4
For j = 1 To 13
n = Int(Rnd * 4 + 1)
Do While MyNum(n) = 13
n = Int(Rnd * 4 + 1)
Loop
d(i, j) = n
MyNum(n) = MyNum(n) + 1
Next j
Next i
End Function
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