关联查询即可实现,表1关联表2,条件就是你如何从表1找到表2,关联后可以同时获取两个表的所有字段,就可以过滤字段,指定显示的字段,格式参考:select a.字段,b.genger from 表1 a join 表2 b on a.条件字段=b.条件字段。
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update table set name='f' where id = 1;
update table set name='f' where id 1 id 5;
什么数据库?\x0d\x0a如果是 Oracle 或者 SQL Server 的话。 可以\x0d\x0a\x0d\x0aSELECT\x0d\x0a *\x0d\x0aFROM\x0d\x0a(\x0d\x0a SELECT ROW_NUMBER() OVER( ORDER BY 排序的字段 ) AS 序号\x0d\x0a 表.*\x0d\x0a FROM\x0d\x0a 表\x0d\x0a) tmp\x0d\x0aWHERE\x0d\x0a tmp.序号 = 12345\x0d\x0a\x0d\x0a如果是 MySQL 的话, 直接\x0d\x0aSELECT * FROM 表 LIMIT 12344, 1\x0d\x0a注:\x0d\x0aLIMIT 接受一个或两个数字参数。\x0d\x0a参数必须是一个整数常量。\x0d\x0a如果给定两个参数,第一个参数指定第一个返回记录行的偏移量,\x0d\x0a第二个参数指定返回记录行的最大数目。\x0d\x0a初始记录行的偏移量是 0(而不是 1)
select *
from 表名
limit 10, 11
注:第10条到第20条共计11条记录
mysql如何指定查询一张表的查询结果,如最后5行记录和最前5行记录
mysql如何指定查询一张表的查询结果,如最后5行记录和最前5行记录
我们以student表为例,里面有三个字段:id,name,age,其中id为主健,为自增,里面共有10条记录,如下所示。
mysql select * from student;
+----+------+------+
| id | name | age |
+----+------+------+
| 1 | li | 11 |
| 2 | zh | 12 |
| 3 | chou | 13 |
| 4 | he | 14 |
| 5 | lin | 15 |
| 6 | ll | 16 |
| 7 | chen | 17 |
| 8 | yu | 18 |
| 9 | wu | 19 |
| 10 | xie | 20 |
+----+------+------+
10 rows in set (0.00 sec)
1、查询第一行记录
select * from student limit 1;
+----+------+------+
| id | name | age |
+----+------+------+
| 1 | li | 11 |
+----+------+------+
1 row in set (0.00 sec)
2、查询最后一行记录
select * from student order by id desc limit 1;
+----+------+------+
| id | name | age |
+----+------+------+
| 10 | xie | 20 |
+----+------+------+
1 row in set (0.00 sec)
3、查询前n行记录,如前5行
select * from student limit 5;
select * from student limit 0,5;
select * from student order by id asc limit 5;
上面三条语句的结果都是一样的,如下:
+----+------+------+
| id | name | age |
+----+------+------+
| 1 | li | 11 |
| 2 | zh | 12 |
| 3 | chou | 13 |
| 4 | he | 14 |
| 5 | lin | 15 |
+----+------+------+
5 rows in set (0.00 sec)
4、查询后n行记录,如后5条,注意结果为倒序排序,因为用了desc
select * from student order by id desc limit 5;
+----+------+------+
| id | name | age |
+----+------+------+
| 10 | xie | 20 |
| 9 | wu | 19 |
| 8 | yu | 18 |
| 7 | chen | 17 |
| 6 | ll | 16 |
+----+------+------+
5 rows in set (0.00 sec)
5、查询第m行到第n行记录,注意表中的记录下标是从0开始的,就像数组一样
select * from student limit m,n; 返回m+1到m+n行记录,m代表开始的下标,n代表查找的结果数,将返回n行结果
select * from student limit 2,8; 返回3到10行记录
+----+------+------+
| id | name | age |
+----+------+------+
| 3 | chou | 13 |
| 4 | he | 14 |
| 5 | lin | 15 |
| 6 | ll | 16 |
| 7 | chen | 17 |
| 8 | yu | 18 |
| 9 | wu | 19 |
| 10 | xie | 20 |
+----+------+------+
8 rows in set (0.00 sec)
select * from student limit 3,1; 返回第4行
+----+------+------+
| id | name | age |
+----+------+------+
| 4 | he | 14 |
+----+------+------+
1 row in set (0.00 sec)
6、查询一条记录($id)的下一条记录
select * from student where id$id order by id asc limit 1;
如$id=4时将返回第5条记录
select * from student where id4 order by id asc limit 1;
+----+------+------+
| id | name | age |
+----+------+------+
| 5 | lin | 15 |
+----+------+------+
1 row in set (0.00 sec)
7、查询一条记录($id)的上一条记录
select * from student where id$id order by id desc limit 1;
如$id=4时将返回第3条记录
select * from student where id4 order by id desc limit 1;
+----+------+------+
| id | name | age |
+----+------+------+
| 3 | chou | 13 |
+----+------+------+
1 row in set (0.00 sec)
1、创建测试表,
create table test_limit(id int ,value varchar(100));
2、插入测试数据,共6条记录;
insert into test_limit values (1,'v1');
insert into test_limit values (2,'v2');
insert into test_limit values (3,'v3');
insert into test_limit values (4,'v4');
insert into test_limit values (5,'v5');
insert into test_limit values (6,'v6');
3、查询表中全量数据,可以发现共6条数据,select * from test_limit t;
4、编写语句,指定查询3条数据;
select * from test_limit limit 3;
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