java练习题求完整代码

按照题目要求编写的用javaBean规范设计的学生类Student的Java程序如下

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需要创建user.java.test包,把Student.java文件和Test.java文件放入包中,编译Student.java文件并且编译运行Test.java文件得到运行结果

Student.java文件代码如下

package user.java.test;

import java.io.Serializable;

public class Student implements Serializable{

private static final long serialVersionUID = 1L;

private String no;

private String name;

private double score;

public Student(){}

public Student(String no,String name,double score){

this.no=no;

this.name=name;

this.score=score;

}

public String getNo(){ return no;}

public void setNo(String no){ this.no=no;}

public String getName(){ return name;}

public void setName(String name){ this.name=name;}

public double getScore(){ return score;}

public void setScore(double score){ this.score=score;}

public String toString(){

return "学号:"+no+",姓名:"+name+",成绩:"+score;

}

public static double getAvg(Student[] sArray){

double sum=0,avg;

for(int i=0;isArray.length;i++){

sum=sum+sArray[i].getScore();

}

avg=sum/sArray.length;

return avg;

}

}

Test.java文件代码如下

package user.java.test;

public class Test{

public static void main(String[] args){

Student[] sArray=new Student[5];

sArray[0]=new Student("001","张三",89.5);

sArray[1]=new Student("002","李四",82.5);

sArray[2]=new Student("003","王五",93);

sArray[3]=new Student("004","赵六",73.5);

sArray[4]=new Student("005","孙七",66);

System.out.println("这些学生的平均分:"+Student.getAvg(sArray));

for(int i=0;isArray.length;i++){

System.out.println(sArray[i].toString());

}

}

}

java面试题求代码，最好有注解。。。

你好，代码如下。需要修改的话，你可以根据情况修改：

class Info{ // 定义信息类

private String name = "生产者"; // 定义name属性

private String content = "压入子弹" ; // 定义content属性

private boolean flag = false ; // 设置标志位

public synchronized void set(String name,String content){

if(!flag){

try{

super.wait() ;

}catch(InterruptedException e){

e.printStackTrace() ;

}

}

this.setName(name) ; // 设置名称

try{

Thread.sleep(300) ;

}catch(InterruptedException e){

e.printStackTrace() ;

}

this.setContent(content) ; // 设置内容

flag = false ; // 改变标志位，表示可以取走

super.notify() ;

}

public synchronized void get(){

if(flag){

try{

super.wait() ;

}catch(InterruptedException e){

e.printStackTrace() ;

}

}

try{

Thread.sleep(300) ;

}catch(InterruptedException e){

e.printStackTrace() ;

}

System.out.println(this.getName() +

" -- " + this.getContent()) ;

flag = true ; // 改变标志位，表示可以生产

super.notify() ;

}

public void setName(String name){

this.name = name ;

}

public void setContent(String content){

this.content = content ;

}

public String getName(){

return this.name ;

}

public String getContent(){

return this.content ;

}

};

class Producer implements Runnable{ // 通过Runnable实现多线程

private Info info = null ; // 保存Info引用

public Producer(Info info){

this.info = info ;

}

public void run(){

boolean flag = false ; // 定义标记位

for(int i=0;i12;i++){

if(flag){

this.info.set("生产者","压入子弹") ; // 设置名称

flag = false ;

}else{

this.info.set("消费者","射出子弹") ; // 设置名称

flag = true ;

}

}

}

};

class Consumer implements Runnable{

private Info info = null ;

public Consumer(Info info){

this.info = info ;

}

public void run(){

for(int i=0;i24;i++){

this.info.get() ;

}

}

};

public class ThreadCaseDemo03{

public static void main(String args[]){

Info info = new Info(); // 实例化Info对象

Producer pro = new Producer(info) ; // 生产者

Consumer con = new Consumer(info) ; // 消费者

new Thread(pro).start() ;

new Thread(con).start() ;

}

};

请求大神帮我解答这道java编程题（填写代码）

此题的Employee类设计有缺陷，缺少员工薪水的属性。根据题意只能写出下面的程序：

abstract class Employee {

public abstract double earnings();

}

class YearWorker extends Employee {

@Override

public double earnings() {

return 0;

}

}

class MonthWorker extends Employee {

@Override

public double earnings() {

return 0;

}

}

class WeekWorker extends Employee {

@Override

public double earnings() {

return 0;

}

}

class Company {

Employee[] employee;

double salaries = 0;

Company(Employee[] employee) {

this.employee = employee;

}

public double salariesPay() {

salaries = 0;

//计算salaries

for(int i=0; iemployee.length; i++) {

salaries += employee[i].earnings();

}

return salaries;

}

}

public class HardWork {

public static void main(String[] args) {

Employee[] employee = new Employee[20];

for(int i=0; iemployee.length; i++) {

if(i % 3 == 0) {

employee[i] = new YearWorker();

}

else if(i % 3 == 1) {

employee[i] = new MonthWorker();

}

else if(i % 3 == 2) {

employee[i] = new WeekWorker();

}

}

Company company = new Company(employee);

System.out.println("公司年工资总额:" + company.salariesPay());

}

}

运行结果：

公司年工资总额:0.0

求解一道Java实验题，给出一段代码，要求把该代码补充完整使其可以运行，具体要求如下

package xinguan;

abstract class Operation{ //抽象类

public static double numberA= 0;

public static double numberB = 0;

abstract double getResult(); //抽象方法

}

class OperationADD extends Operation{

@Override

double getResult() {

return numberA+numberB;

}

}

class OperationSUB extends Operation{

@Override

double getResult() {

return numberA-numberB;

}

}

class OperationMUL extends Operation{

@Override

double getResult() {

return numberA*numberB;

}

}

class OperationDIV extends Operation{

@Override

double getResult() {

return numberA/numberB;

}

}

class OperationFactory{

public static Operation createOperate(char operate){

Operation oper = null;

switch (operate){

case'+':

oper= new OperationADD();

break;

case'-':

oper= new OperationSUB();

break;

case'*':

oper= new OperationMUL();

break;

case'/':

oper= new OperationDIV();

break;

}

return oper;

}

}

public class CalculateDemo {

/**

* @param args

*/

public static void main(String[] args) {

Operation operADD = OperationFactory.createOperate('+');

Operation operSUB = OperationFactory.createOperate('-');

Operation operMUL = OperationFactory.createOperate('*');

Operation operDIV = OperationFactory.createOperate('/');

operADD.numberA = 15.0;

operADD.numberB = 3;

System.out.println(operADD.getResult());

System.out.println(operSUB.getResult());

System.out.println(operMUL.getResult());

System.out.println(operDIV.getResult());

}

}

因为抽象类是静态方法 所以 给operADD 那个对象赋值一次就能获得所有结果。要是去掉static 那么就需要每个对象 赋值。现在基本满足你的要求了。